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Rank the Vertical Velocity from Largest to smallest
Rank the horizontal displacement
from least to greatest.
Explain.
The football has 2 velocities.
Which velocity is the football player matching.
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Horizontal velocity.
The football and the football player
have a constant horizontal velocity.
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Ex) A projectile leaves ground at an angle
of 60.° and a speed of 100.m/s.
(a) Find the initial vertical
component of the object's velocity

Ex) A
projectile leaves ground at
an angle of 60.°
and a speed of
100. m/s.
(a) Find the
initial vertical component
of the object's velocity
Ө = 60.°
V_{i} = 100. m/s
V_{iy} = ?
V_{iy}
= V_{i}(sinӨ)
= (100. m/s)sin60.°
V_{iy} = 87. m/s up
(b) Find
the objects
maximum height.
V_{iy} = 87. m/s
a_{y} = 10 m/s^{2} (ascending)
d_{y} (max) =?
V_{fy} = 0 (at
max height)
V_{f}^{2} = V_{iy}^{2}
+ 2ad
0^{2} = (87. m/s)^{2}
+ 2(9.8 m/s^{2})d
0 = 7569 + 19.6.d_{y}
subtract 7569 from both sides
7569 = 19.g(d_{y})
d_{y} = 386 m
Actually ......
d_{y} = 390 m
(2 sig. figs)
ex) A rock is thrown from a cliff with
initial speed of 40. m/s at an angle of 45.° below the horizontal.
(a) What is the vertical component of the
initial velocity?

a) What is the
vertical component
of the initial
velocity?
Ө = 45.°
V_{i} = 40. m/s
V_{iy} = ?
V_{iy} = VsinӨ
(b) If the
rock strikes ground in 1 sec what is height of cliff?
(b) If the
rock strikes ground in 1.0 sec what
is
height of cliff?
d_{y} = ?
(height)
a_{y} = + 9.8 m/s^{2}
t = 1.0 sec
V_{iy} = 28 m/s
(from before)
d_{y} = V_{iy}t + (˝)at^{2}
= 28.m/s(1sec)+˝(9.8 m/s^{2})(1.0sec)^{2}
28 m + 4.9 m
d_{y} = 32.9 m down
d_{y} = 33 m down
At Peak,
V_{x}
= ?
V_{x}
= 9.0 m/s
Total Time in Air?
1.84 sec
(twice peak)
actually 1.8
(2 sig. figs.)
What will the horizontal velocity of the baseball be
just before it hits the ground?
9 m/s, Vx is constant
Monkey and
Hunter
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(offsite)
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Physics  Don Ion
St.
Mary's U. Astronomy and Physics Dept.

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